Base | Representation |
---|---|
bin | 1100010010111110110010… |
… | …0101111101101100101011 |
3 | 1202212112002011202200001211 |
4 | 3010233230211331230223 |
5 | 3233003413223034111 |
6 | 44431035242053551 |
7 | 2563542640122313 |
oct | 304575445755453 |
9 | 52775064680054 |
10 | 13520231455531 |
11 | 4342997204179 |
12 | 162438a1aa2b7 |
13 | 770c4c42c748 |
14 | 34a550180443 |
15 | 186a5b505521 |
hex | c4bec97db2b |
13520231455531 has 4 divisors (see below), whose sum is σ = 13520480221864. Its totient is φ = 13519982689200.
The previous prime is 13520231455513. The next prime is 13520231455547. The reversal of 13520231455531 is 13555413202531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13520231455531 - 25 = 13520231455499 is a prime.
It is a super-2 number, since 2×135202314555312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13520231455501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124301625 + ... + 124410346.
It is an arithmetic number, because the mean of its divisors is an integer number (3380120055466).
Almost surely, 213520231455531 is an apocalyptic number.
13520231455531 is a deficient number, since it is larger than the sum of its proper divisors (248766333).
13520231455531 is an equidigital number, since it uses as much as digits as its factorization.
13520231455531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 248766332.
The product of its (nonzero) digits is 270000, while the sum is 40.
The spelling of 13520231455531 in words is "thirteen trillion, five hundred twenty billion, two hundred thirty-one million, four hundred fifty-five thousand, five hundred thirty-one".
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