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1352031757113 = 3450677252371
BaseRepresentation
bin10011101011001011010…
…111110110001100111001
311210020211102021120122110
4103223023113312030321
5134122430112211423
62513040444442533
7166452415213302
oct23531327661471
94706742246573
101352031757113
11481436752454
1219a048849449
139a65aa801bb
144961da7d7a9
1525281d52193
hex13acb5f6339

1352031757113 has 4 divisors (see below), whose sum is σ = 1802709009488. Its totient is φ = 901354504740.

The previous prime is 1352031757033. The next prime is 1352031757147. The reversal of 1352031757113 is 3117571302531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1352031757113 - 28 = 1352031756857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1352031757513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225338626183 + ... + 225338626188.

It is an arithmetic number, because the mean of its divisors is an integer number (450677252372).

Almost surely, 21352031757113 is an apocalyptic number.

It is an amenable number.

1352031757113 is a deficient number, since it is larger than the sum of its proper divisors (450677252375).

1352031757113 is an equidigital number, since it uses as much as digits as its factorization.

1352031757113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 450677252374.

The product of its (nonzero) digits is 66150, while the sum is 39.

The spelling of 1352031757113 in words is "one trillion, three hundred fifty-two billion, thirty-one million, seven hundred fifty-seven thousand, one hundred thirteen".

Divisors: 1 3 450677252371 1352031757113