13520342425433 has 4 divisors (see below), whose sum is σ = 13521540305280. Its totient is φ = 13519144545588.

The previous prime is 13520342425411. The next prime is 13520342425451. The reversal of 13520342425433 is 33452424302531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13520342425433 - 2¹⁰ = 13520342424409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13520342425633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 598922993 + ... + 598945566.

It is an arithmetic number, because the mean of its divisors is an integer number (3380385076320).

Almost surely, 2^{13520342425433} is an apocalyptic number.

It is an amenable number.

13520342425433 is a deficient number, since it is larger than the sum of its proper divisors (1197879847).

13520342425433 is a wasteful number, since it uses less digits than its factorization.

13520342425433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1197879846.

The product of its (nonzero) digits is 1036800, while the sum is 41.

Adding to 13520342425433 its reverse (33452424302531), we get a palindrome (46972766727964).

The spelling of 13520342425433 in words is "thirteen trillion, five hundred twenty billion, three hundred forty-two million, four hundred twenty-five thousand, four hundred thirty-three".