135208043401 has 4 divisors (see below), whose sum is σ = 136272673792. Its totient is φ = 134143413012.

The previous prime is 135208043357. The next prime is 135208043449. The reversal of 135208043401 is 104340802531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104340802531 = 7 ⋅14905828933.

It is a cyclic number.

It is not a de Polignac number, because 135208043401 - 2¹⁵ = 135208010633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135208049401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532315005 + ... + 532315258.

It is an arithmetic number, because the mean of its divisors is an integer number (34068168448).

Almost surely, 2^135208043401 is an apocalyptic number.

It is an amenable number.

135208043401 is a deficient number, since it is larger than the sum of its proper divisors (1064630391).

135208043401 is a wasteful number, since it uses less digits than its factorization.

135208043401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1064630390.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 135208043401 its reverse (104340802531), we get a palindrome (239548845932).

The spelling of 135208043401 in words is "one hundred thirty-five billion, two hundred eight million, forty-three thousand, four hundred one".