Base | Representation |
---|---|
bin | 111110111101100110… |
… | …1100110101010011011 |
3 | 110221000002122002111121 |
4 | 1331323031212222123 |
5 | 4203403023244404 |
6 | 142040512110111 |
7 | 12524441545303 |
oct | 1757315465233 |
9 | 427002562447 |
10 | 135211149979 |
11 | 52385195254 |
12 | 22255b35337 |
13 | c99a6c2829 |
14 | 6789612603 |
15 | 37b55c7e54 |
hex | 1f7b366a9b |
135211149979 has 4 divisors (see below), whose sum is σ = 135217561984. Its totient is φ = 135204737976.
The previous prime is 135211149977. The next prime is 135211149989. The reversal of 135211149979 is 979941112531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 979941112531 = 191 ⋅5130581741.
It is a cyclic number.
It is not a de Polignac number, because 135211149979 - 21 = 135211149977 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135211149971) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3174267 + ... + 3216580.
It is an arithmetic number, because the mean of its divisors is an integer number (33804390496).
Almost surely, 2135211149979 is an apocalyptic number.
135211149979 is a deficient number, since it is larger than the sum of its proper divisors (6412005).
135211149979 is an equidigital number, since it uses as much as digits as its factorization.
135211149979 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6412004.
The product of its digits is 612360, while the sum is 52.
The spelling of 135211149979 in words is "one hundred thirty-five billion, two hundred eleven million, one hundred forty-nine thousand, nine hundred seventy-nine".
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