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13521310143313 = 71931615734759
BaseRepresentation
bin1100010011000010110011…
…1000110101001101010001
31202212121212100111200112011
43010300230320311031101
53233013120344041223
644431334254102521
72563611445612540
oct304605470651521
952777770450464
1013521310143313
1143433a0092285
12162462b4aaa41
13771091a5a93b
1434a613532157
15186ac107b80d
hexc4c2ce35351

13521310143313 has 4 divisors (see below), whose sum is σ = 15452925878080. Its totient is φ = 11589694408548.

The previous prime is 13521310143259. The next prime is 13521310143391. The reversal of 13521310143313 is 31334101312531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13521310143313 - 213 = 13521310135121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13521310143613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 965807867373 + ... + 965807867386.

It is an arithmetic number, because the mean of its divisors is an integer number (3863231469520).

Almost surely, 213521310143313 is an apocalyptic number.

It is an amenable number.

13521310143313 is a deficient number, since it is larger than the sum of its proper divisors (1931615734767).

13521310143313 is an equidigital number, since it uses as much as digits as its factorization.

13521310143313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1931615734766.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 13521310143313 its reverse (31334101312531), we get a palindrome (44855411455844).

The spelling of 13521310143313 in words is "thirteen trillion, five hundred twenty-one billion, three hundred ten million, one hundred forty-three thousand, three hundred thirteen".

Divisors: 1 7 1931615734759 13521310143313