13521443401 has 4 divisors (see below), whose sum is σ = 13987700100. Its totient is φ = 13055186704.

The previous prime is 13521443399. The next prime is 13521443407. The reversal of 13521443401 is 10434412531.

13521443401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5034612025 + 8486831376 = 70955^2 + 92124^2 .

It is a cyclic number.

It is not a de Polignac number, because 13521443401 - 2¹ = 13521443399 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13521443401.

It is not an unprimeable number, because it can be changed into a prime (13521443407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233128306 + ... + 233128363.

It is an arithmetic number, because the mean of its divisors is an integer number (3496925025).

Almost surely, 2^13521443401 is an apocalyptic number.

It is an amenable number.

13521443401 is a deficient number, since it is larger than the sum of its proper divisors (466256699).

13521443401 is an equidigital number, since it uses as much as digits as its factorization.

13521443401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 466256698.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 13521443401 its reverse (10434412531), we get a palindrome (23955855932).

The spelling of 13521443401 in words is "thirteen billion, five hundred twenty-one million, four hundred forty-three thousand, four hundred one".