Base | Representation |
---|---|
bin | 111110111101111111… |
… | …1001111111100010001 |
3 | 110221001000010021112120 |
4 | 1331323333033330101 |
5 | 4203414341222423 |
6 | 142042055044453 |
7 | 12524660300343 |
oct | 1757377177421 |
9 | 427030107476 |
10 | 135224164113 |
11 | 52391573a35 |
12 | 2225a370729 |
13 | c9a02cb2bc |
14 | 678b23d293 |
15 | 37b67e8ee3 |
hex | 1f7bfcff11 |
135224164113 has 4 divisors (see below), whose sum is σ = 180298885488. Its totient is φ = 90149442740.
The previous prime is 135224164099. The next prime is 135224164121. The reversal of 135224164113 is 311461422531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 135224164113 - 29 = 135224163601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (135224164123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22537360683 + ... + 22537360688.
It is an arithmetic number, because the mean of its divisors is an integer number (45074721372).
Almost surely, 2135224164113 is an apocalyptic number.
It is an amenable number.
135224164113 is a deficient number, since it is larger than the sum of its proper divisors (45074721375).
135224164113 is an equidigital number, since it uses as much as digits as its factorization.
135224164113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45074721374.
The product of its digits is 17280, while the sum is 33.
Adding to 135224164113 its reverse (311461422531), we get a palindrome (446685586644).
The spelling of 135224164113 in words is "one hundred thirty-five billion, two hundred twenty-four million, one hundred sixty-four thousand, one hundred thirteen".
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