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1352441105115 = 35113797900357
BaseRepresentation
bin10011101011100011110…
…001011000101011011011
311210021212221112121112120
4103223203301120223123
5134124244410330430
62513145230312323
7166465515500562
oct23534361305333
94707787477476
101352441105115
11481626822691
1219a1419586a3
139a6c4815659
144965c198bd9
15252a7c60610
hex13ae3c58adb

1352441105115 has 16 divisors (see below), whose sum is σ = 2183055379488. Its totient is φ = 714918718976.

The previous prime is 1352441105087. The next prime is 1352441105167. The reversal of 1352441105115 is 5115011442531.

It is a cyclic number.

It is not a de Polignac number, because 1352441105115 - 29 = 1352441104603 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 398948484 + ... + 398951873.

It is an arithmetic number, because the mean of its divisors is an integer number (136440961218).

Almost surely, 21352441105115 is an apocalyptic number.

1352441105115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1352441105115 is a deficient number, since it is larger than the sum of its proper divisors (830614274373).

1352441105115 is a wasteful number, since it uses less digits than its factorization.

1352441105115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 797900478.

The product of its (nonzero) digits is 12000, while the sum is 33.

Adding to 1352441105115 its reverse (5115011442531), we get a palindrome (6467452547646).

The spelling of 1352441105115 in words is "one trillion, three hundred fifty-two billion, four hundred forty-one million, one hundred five thousand, one hundred fifteen".

Divisors: 1 3 5 15 113 339 565 1695 797900357 2393701071 3989501785 11968505355 90162740341 270488221023 450813701705 1352441105115