Base | Representation |
---|---|
bin | 10011101011100011110… |
… | …001011000101011011011 |
3 | 11210021212221112121112120 |
4 | 103223203301120223123 |
5 | 134124244410330430 |
6 | 2513145230312323 |
7 | 166465515500562 |
oct | 23534361305333 |
9 | 4707787477476 |
10 | 1352441105115 |
11 | 481626822691 |
12 | 19a1419586a3 |
13 | 9a6c4815659 |
14 | 4965c198bd9 |
15 | 252a7c60610 |
hex | 13ae3c58adb |
1352441105115 has 16 divisors (see below), whose sum is σ = 2183055379488. Its totient is φ = 714918718976.
The previous prime is 1352441105087. The next prime is 1352441105167. The reversal of 1352441105115 is 5115011442531.
It is a cyclic number.
It is not a de Polignac number, because 1352441105115 - 29 = 1352441104603 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 398948484 + ... + 398951873.
It is an arithmetic number, because the mean of its divisors is an integer number (136440961218).
Almost surely, 21352441105115 is an apocalyptic number.
1352441105115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1352441105115 is a deficient number, since it is larger than the sum of its proper divisors (830614274373).
1352441105115 is a wasteful number, since it uses less digits than its factorization.
1352441105115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 797900478.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 1352441105115 its reverse (5115011442531), we get a palindrome (6467452547646).
The spelling of 1352441105115 in words is "one trillion, three hundred fifty-two billion, four hundred forty-one million, one hundred five thousand, one hundred fifteen".
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