Base | Representation |
---|---|
bin | 10011101011111010101… |
… | …101010011010111100001 |
3 | 11210022212202121202122020 |
4 | 103223322231103113201 |
5 | 134131041413121003 |
6 | 2513251334132053 |
7 | 166511200340112 |
oct | 23537255232741 |
9 | 4708782552566 |
10 | 1352825910753 |
11 | 481803a5a879 |
12 | 19a22a7b1029 |
13 | 9a756466cb5 |
14 | 49697326209 |
15 | 252cb921d53 |
hex | 13afab535e1 |
1352825910753 has 4 divisors (see below), whose sum is σ = 1803767881008. Its totient is φ = 901883940500.
The previous prime is 1352825910731. The next prime is 1352825910763. The reversal of 1352825910753 is 3570195282531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1352825910753 - 217 = 1352825779681 is a prime.
It is a super-3 number, since 3×13528259107533 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1352825910696 and 1352825910705.
It is not an unprimeable number, because it can be changed into a prime (1352825910763) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225470985123 + ... + 225470985128.
It is an arithmetic number, because the mean of its divisors is an integer number (450941970252).
Almost surely, 21352825910753 is an apocalyptic number.
It is an amenable number.
1352825910753 is a deficient number, since it is larger than the sum of its proper divisors (450941970255).
1352825910753 is an equidigital number, since it uses as much as digits as its factorization.
1352825910753 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 450941970254.
The product of its (nonzero) digits is 2268000, while the sum is 51.
The spelling of 1352825910753 in words is "one trillion, three hundred fifty-two billion, eight hundred twenty-five million, nine hundred ten thousand, seven hundred fifty-three".
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