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13532013003 = 34510671001
BaseRepresentation
bin11001001101001001…
…00010000111001011
31021221001212111002210
430212210202013023
5210203143404003
610114434000203
7656223132645
oct144644420713
937831774083
1013532013003
115814517723
122757a16063
1313786850b2
14925295895
15542ee0503
hex3269221cb

13532013003 has 4 divisors (see below), whose sum is σ = 18042684008. Its totient is φ = 9021342000.

The previous prime is 13532012999. The next prime is 13532013007. The reversal of 13532013003 is 30031023531.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13532012999) and next prime (13532013007).

It is not a de Polignac number, because 13532013003 - 22 = 13532012999 is a prime.

It is a super-2 number, since 2×135320130032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13532013007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2255335498 + ... + 2255335503.

It is an arithmetic number, because the mean of its divisors is an integer number (4510671002).

Almost surely, 213532013003 is an apocalyptic number.

13532013003 is a deficient number, since it is larger than the sum of its proper divisors (4510671005).

13532013003 is an equidigital number, since it uses as much as digits as its factorization.

13532013003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4510671004.

The product of its (nonzero) digits is 810, while the sum is 21.

Adding to 13532013003 its reverse (30031023531), we get a palindrome (43563036534).

The spelling of 13532013003 in words is "thirteen billion, five hundred thirty-two million, thirteen thousand, three".

Divisors: 1 3 4510671001 13532013003