Base | Representation |
---|---|
bin | 10011101100010111001… |
… | …111001011011011000011 |
3 | 11210101010010021022120121 |
4 | 103230113033023123003 |
5 | 134133031431200110 |
6 | 2513411033121111 |
7 | 166526101622032 |
oct | 23542717133303 |
9 | 4711103238517 |
10 | 1353304553155 |
11 | 481a2a159a05 |
12 | 19a342b59197 |
13 | 9a801681a59 |
14 | 49700b1c719 |
15 | 2530896bcda |
hex | 13b173cb6c3 |
1353304553155 has 4 divisors (see below), whose sum is σ = 1623965463792. Its totient is φ = 1082643642520.
The previous prime is 1353304553149. The next prime is 1353304553191. The reversal of 1353304553155 is 5513554033531.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1353304553155 - 23 = 1353304553147 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135330455311 + ... + 135330455320.
It is an arithmetic number, because the mean of its divisors is an integer number (405991365948).
Almost surely, 21353304553155 is an apocalyptic number.
1353304553155 is a deficient number, since it is larger than the sum of its proper divisors (270660910637).
1353304553155 is an equidigital number, since it uses as much as digits as its factorization.
1353304553155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 270660910636.
The product of its (nonzero) digits is 1012500, while the sum is 43.
Adding to 1353304553155 its reverse (5513554033531), we get a palindrome (6866858586686).
The spelling of 1353304553155 in words is "one trillion, three hundred fifty-three billion, three hundred four million, five hundred fifty-three thousand, one hundred fifty-five".
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