13533312113 has 4 divisors (see below), whose sum is σ = 13537392960. Its totient is φ = 13529231268.

The previous prime is 13533312097. The next prime is 13533312137. The reversal of 13533312113 is 31121333531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121333531 = 257 ⋅121094683.

It is a cyclic number.

It is not a de Polignac number, because 13533312113 - 2⁴ = 13533312097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13533312193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2035445 + ... + 2042082.

It is an arithmetic number, because the mean of its divisors is an integer number (3384348240).

Almost surely, 2^13533312113 is an apocalyptic number.

It is an amenable number.

13533312113 is a deficient number, since it is larger than the sum of its proper divisors (4080847).

13533312113 is an equidigital number, since it uses as much as digits as its factorization.

13533312113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4080846.

The product of its digits is 2430, while the sum is 26.

Adding to 13533312113 its reverse (31121333531), we get a palindrome (44654645644).

The spelling of 13533312113 in words is "thirteen billion, five hundred thirty-three million, three hundred twelve thousand, one hundred thirteen".