Base | Representation |
---|---|
bin | 1100010011101111100011… |
… | …1111100110010111101001 |
3 | 1202220202212122110101010122 |
4 | 3010323320333212113221 |
5 | 3233212222021413301 |
6 | 44441042353253025 |
7 | 2564515252263320 |
oct | 304737077462751 |
9 | 52822778411118 |
10 | 13533324404201 |
11 | 43484a58a4308 |
12 | 1626a22b64175 |
13 | 772257b46554 |
14 | 34b032dc30b7 |
15 | 187075bb781b |
hex | c4ef8fe65e9 |
13533324404201 has 8 divisors (see below), whose sum is σ = 15678528468864. Its totient is φ = 11441088341280.
The previous prime is 13533324404191. The next prime is 13533324404207. The reversal of 13533324404201 is 10240442333531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13533324404201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13533324404207) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13241999885 + ... + 13242000906.
It is an arithmetic number, because the mean of its divisors is an integer number (1959816058608).
Almost surely, 213533324404201 is an apocalyptic number.
It is an amenable number.
13533324404201 is a deficient number, since it is larger than the sum of its proper divisors (2145204064663).
13533324404201 is an equidigital number, since it uses as much as digits as its factorization.
13533324404201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26484000871.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 13533324404201 its reverse (10240442333531), we get a palindrome (23773766737732).
The spelling of 13533324404201 in words is "thirteen trillion, five hundred thirty-three billion, three hundred twenty-four million, four hundred four thousand, two hundred one".
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