13533340113 has 20 divisors (see below), whose sum is σ = 20762866740. Its totient is φ = 8778380832.

The previous prime is 13533340111. The next prime is 13533340123. The reversal of 13533340113 is 31104333531.

13533340113 is a `hidden beast` number, since 13 + 533 + 3 + 4 + 0 + 113 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 13163431824 + 369908289 = 114732^2 + 19233^2 .

It is not a de Polignac number, because 13533340113 - 2¹ = 13533340111 is a prime.

It is a super-2 number, since 2×13533340113² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (13533340111) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 2254818 + ... + 2260811.

It is an arithmetic number, because the mean of its divisors is an integer number (1038143337).

Almost surely, 2^13533340113 is an apocalyptic number.

It is an amenable number.

13533340113 is a deficient number, since it is larger than the sum of its proper divisors (7229526627).

13533340113 is an equidigital number, since it uses as much as digits as its factorization.

13533340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4515678 (or 4515669 counting only the distinct ones).

The product of its (nonzero) digits is 4860, while the sum is 27.

Adding to 13533340113 its reverse (31104333531), we get a palindrome (44637673644).

The spelling of 13533340113 in words is "thirteen billion, five hundred thirty-three million, three hundred forty thousand, one hundred thirteen".