Base | Representation |
---|---|
bin | 111111000001011100… |
… | …0011101011100110011 |
3 | 110221100001202110101011 |
4 | 1332002320131130303 |
5 | 4204133443344242 |
6 | 142101350051351 |
7 | 12530563350055 |
oct | 1760270353463 |
9 | 427301673334 |
10 | 135339824947 |
11 | 524408916a8 |
12 | 22291049b57 |
13 | c9bb266172 |
14 | 679c7498d5 |
15 | 37c1a43d17 |
hex | 1f82e1d733 |
135339824947 has 4 divisors (see below), whose sum is σ = 135648116560. Its totient is φ = 135031533336.
The previous prime is 135339824923. The next prime is 135339824953. The reversal of 135339824947 is 749428933531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 749428933531 = 463103 ⋅1618277.
It is a cyclic number.
It is not a de Polignac number, because 135339824947 - 211 = 135339822899 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135339824891 and 135339824900.
It is not an unprimeable number, because it can be changed into a prime (135339824447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154145148 + ... + 154146025.
It is an arithmetic number, because the mean of its divisors is an integer number (33912029140).
Almost surely, 2135339824947 is an apocalyptic number.
135339824947 is a deficient number, since it is larger than the sum of its proper divisors (308291613).
135339824947 is an equidigital number, since it uses as much as digits as its factorization.
135339824947 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 308291612.
The product of its digits is 19595520, while the sum is 58.
The spelling of 135339824947 in words is "one hundred thirty-five billion, three hundred thirty-nine million, eight hundred twenty-four thousand, nine hundred forty-seven".
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