Base | Representation |
---|---|
bin | 11001001101011001… |
… | …00010100100110011 |
3 | 1021221012211010110022 |
4 | 30212230202210303 |
5 | 210204213041201 |
6 | 10114550554055 |
7 | 656250024425 |
oct | 144654424463 |
9 | 37835733408 |
10 | 13534112051 |
11 | 5815720779 |
12 | 275866892b |
13 | 1378c3b635 |
14 | 925680815 |
15 | 5432a741b |
hex | 326b22933 |
13534112051 has 4 divisors (see below), whose sum is σ = 14000805600. Its totient is φ = 13067418504.
The previous prime is 13534112041. The next prime is 13534112077. The reversal of 13534112051 is 15021143531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15021143531 = 23 ⋅653093197.
It is a cyclic number.
It is not a de Polignac number, because 13534112051 - 230 = 12460370227 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13534112051.
It is not an unprimeable number, because it can be changed into a prime (13534112041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233346731 + ... + 233346788.
It is an arithmetic number, because the mean of its divisors is an integer number (3500201400).
Almost surely, 213534112051 is an apocalyptic number.
13534112051 is a deficient number, since it is larger than the sum of its proper divisors (466693549).
13534112051 is an equidigital number, since it uses as much as digits as its factorization.
13534112051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 466693548.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 13534112051 its reverse (15021143531), we get a palindrome (28555255582).
The spelling of 13534112051 in words is "thirteen billion, five hundred thirty-four million, one hundred twelve thousand, fifty-one".
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