Base | Representation |
---|---|
bin | 11001001101011010… |
… | …11011011110101011 |
3 | 1021221020020222011220 |
4 | 30212231123132223 |
5 | 210204243021011 |
6 | 10114555553123 |
7 | 656252015106 |
oct | 144655333653 |
9 | 37836228156 |
10 | 13534345131 |
11 | 581586a8aa |
12 | 275875b7a3 |
13 | 1378cc0758 |
14 | 92570173d |
15 | 543301506 |
hex | 326b5b7ab |
13534345131 has 4 divisors (see below), whose sum is σ = 18045793512. Its totient is φ = 9022896752.
The previous prime is 13534345063. The next prime is 13534345243. The reversal of 13534345131 is 13154343531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13534345131 - 27 = 13534345003 is a prime.
It is a super-2 number, since 2×135343451312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13534345092 and 13534345101.
It is not an unprimeable number, because it can be changed into a prime (13534347131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2255724186 + ... + 2255724191.
It is an arithmetic number, because the mean of its divisors is an integer number (4511448378).
Almost surely, 213534345131 is an apocalyptic number.
13534345131 is a deficient number, since it is larger than the sum of its proper divisors (4511448381).
13534345131 is an equidigital number, since it uses as much as digits as its factorization.
13534345131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4511448380.
The product of its digits is 32400, while the sum is 33.
Adding to 13534345131 its reverse (13154343531), we get a palindrome (26688688662).
The spelling of 13534345131 in words is "thirteen billion, five hundred thirty-four million, three hundred forty-five thousand, one hundred thirty-one".
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