1353531154041 has 80 divisors (see below), whose sum is σ = 2270213941248. Its totient is φ = 796694421600.

The previous prime is 1353531154039. The next prime is 1353531154069. The reversal of 1353531154041 is 1404511353531.

1353531154041 is a `hidden beast` number, since 1 + 3 + 53 + 53 + 11 + 540 + 4 + 1 = 666.

It is not a de Polignac number, because 1353531154041 - 2¹ = 1353531154039 is a prime.

It is a super-2 number, since 2×1353531154041² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1353531153987 and 1353531154005.

It is not an unprimeable number, because it can be changed into a prime (1353531154141) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 4078816 + ... + 4398158.

Almost surely, 2^{1353531154041} is an apocalyptic number.

1353531154041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1353531154041 is a deficient number, since it is larger than the sum of its proper divisors (916682787207).

1353531154041 is a wasteful number, since it uses less digits than its factorization.

1353531154041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 319504 (or 319495 counting only the distinct ones).

The product of its (nonzero) digits is 54000, while the sum is 36.

The spelling of 1353531154041 in words is "one trillion, three hundred fifty-three billion, five hundred thirty-one million, one hundred fifty-four thousand, forty-one".