Base | Representation |
---|---|
bin | 1100010011110111010110… |
… | …0110100110110100010011 |
3 | 1202220222021100021212111221 |
4 | 3010331311212212310103 |
5 | 3233231012220120220 |
6 | 44442030034145511 |
7 | 2564621126140612 |
oct | 304756546466423 |
9 | 52828240255457 |
10 | 13535415004435 |
11 | 43493789a21a5 |
12 | 1627307122297 |
13 | 7724cbcc2acc |
14 | 34b190903879 |
15 | 1871494c49aa |
hex | c4f759a6d13 |
13535415004435 has 4 divisors (see below), whose sum is σ = 16242498005328. Its totient is φ = 10828332003544.
The previous prime is 13535415004403. The next prime is 13535415004453. The reversal of 13535415004435 is 53440051453531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13535415004435 - 25 = 13535415004403 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13535415004391 and 13535415004400.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1353541500439 + ... + 1353541500448.
It is an arithmetic number, because the mean of its divisors is an integer number (4060624501332).
Almost surely, 213535415004435 is an apocalyptic number.
13535415004435 is a deficient number, since it is larger than the sum of its proper divisors (2707083000893).
13535415004435 is an equidigital number, since it uses as much as digits as its factorization.
13535415004435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2707083000892.
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 13535415004435 its reverse (53440051453531), we get a palindrome (66975466457966).
The spelling of 13535415004435 in words is "thirteen trillion, five hundred thirty-five billion, four hundred fifteen million, four thousand, four hundred thirty-five".
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