1353632656153 has 4 divisors (see below), whose sum is σ = 1353725787060. Its totient is φ = 1353539525248.

The previous prime is 1353632656099. The next prime is 1353632656163. The reversal of 1353632656153 is 3516562363531.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 482869332544 + 870763323609 = 694888^2 + 933147^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1353632656153 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1353632656097 and 1353632656106.

It is not an unprimeable number, because it can be changed into a prime (1353632656163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46543648 + ... + 46572721.

It is an arithmetic number, because the mean of its divisors is an integer number (338431446765).

Almost surely, 2^{1353632656153} is an apocalyptic number.

It is an amenable number.

1353632656153 is a deficient number, since it is larger than the sum of its proper divisors (93130907).

1353632656153 is an equidigital number, since it uses as much as digits as its factorization.

1353632656153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93130906.

The product of its digits is 4374000, while the sum is 49.

The spelling of 1353632656153 in words is "one trillion, three hundred fifty-three billion, six hundred thirty-two million, six hundred fifty-six thousand, one hundred fifty-three".