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13538312241 = 34512770747
BaseRepresentation
bin11001001101111001…
…00100000000110001
31021221111201112000220
430212330210000301
5210211301442431
610115221003253
7656330520036
oct144674440061
937844645026
1013538312241
11581802a403
122759b53529
131379a7c35c
1492605538d
15543836b96
hex326f24031

13538312241 has 4 divisors (see below), whose sum is σ = 18051082992. Its totient is φ = 9025541492.

The previous prime is 13538312201. The next prime is 13538312251. The reversal of 13538312241 is 14221383531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13538312241 - 221 = 13536215089 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13538312201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2256385371 + ... + 2256385376.

It is an arithmetic number, because the mean of its divisors is an integer number (4512770748).

Almost surely, 213538312241 is an apocalyptic number.

It is an amenable number.

13538312241 is a deficient number, since it is larger than the sum of its proper divisors (4512770751).

13538312241 is an equidigital number, since it uses as much as digits as its factorization.

13538312241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4512770750.

The product of its digits is 17280, while the sum is 33.

Adding to 13538312241 its reverse (14221383531), we get a palindrome (27759695772).

The spelling of 13538312241 in words is "thirteen billion, five hundred thirty-eight million, three hundred twelve thousand, two hundred forty-one".

Divisors: 1 3 4512770747 13538312241