Base | Representation |
---|---|
bin | 11001001110000110… |
… | …00101101100000001 |
3 | 1021221121221102210212 |
4 | 30213003011230001 |
5 | 210212221214131 |
6 | 10115321403505 |
7 | 656351203556 |
oct | 144703055401 |
9 | 37847842725 |
10 | 13540023041 |
11 | 5818a98796 |
12 | 275a639595 |
13 | 137a22ac6c |
14 | 92637ca2d |
15 | 543a73a2b |
hex | 3270c5b01 |
13540023041 has 4 divisors (see below), whose sum is σ = 13562330112. Its totient is φ = 13517715972.
The previous prime is 13540023023. The next prime is 13540023061. The reversal of 13540023041 is 14032004531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13540023041 - 214 = 13540006657 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13540022998 and 13540023016.
It is not an unprimeable number, because it can be changed into a prime (13540023061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11152625 + ... + 11153838.
It is an arithmetic number, because the mean of its divisors is an integer number (3390582528).
Almost surely, 213540023041 is an apocalyptic number.
It is an amenable number.
13540023041 is a deficient number, since it is larger than the sum of its proper divisors (22307071).
13540023041 is an equidigital number, since it uses as much as digits as its factorization.
13540023041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22307070.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 13540023041 its reverse (14032004531), we get a palindrome (27572027572).
The spelling of 13540023041 in words is "thirteen billion, five hundred forty million, twenty-three thousand, forty-one".
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