1354040414737 has 8 divisors (see below), whose sum is σ = 1433716090056. Its totient is φ = 1274367654912.

The previous prime is 1354040414653. The next prime is 1354040414759. The reversal of 1354040414737 is 7374140404531.

It can be written as a sum of positive squares in 4 ways, for example, as 481803962641 + 872236452096 = 694121^2 + 933936^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1354040414737 is a prime.

It is a super-2 number, since 2×1354040414737² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1354040414693 and 1354040414702.

It is not an unprimeable number, because it can be changed into a prime (1354040414537) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 266133 + ... + 1667005.

It is an arithmetic number, because the mean of its divisors is an integer number (179214511257).

Almost surely, 2^{1354040414737} is an apocalyptic number.

1354040414737 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

1354040414737 is a deficient number, since it is larger than the sum of its proper divisors (79675675319).

1354040414737 is a wasteful number, since it uses less digits than its factorization.

1354040414737 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1457747.

The product of its (nonzero) digits is 564480, while the sum is 43.

The spelling of 1354040414737 in words is "one trillion, three hundred fifty-four billion, forty million, four hundred fourteen thousand, seven hundred thirty-seven".