1354044123161 has 4 divisors (see below), whose sum is σ = 1354275866832. Its totient is φ = 1353812379492.

The previous prime is 1354044123143. The next prime is 1354044123221. The reversal of 1354044123161 is 1613214404531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1354044123161 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1354044120161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 115863071 + ... + 115874756.

It is an arithmetic number, because the mean of its divisors is an integer number (338568966708).

Almost surely, 2^{1354044123161} is an apocalyptic number.

It is an amenable number.

1354044123161 is a deficient number, since it is larger than the sum of its proper divisors (231743671).

1354044123161 is an equidigital number, since it uses as much as digits as its factorization.

1354044123161 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231743670.

The product of its (nonzero) digits is 34560, while the sum is 35.

Adding to 1354044123161 its reverse (1613214404531), we get a palindrome (2967258527692).

The spelling of 1354044123161 in words is "one trillion, three hundred fifty-four billion, forty-four million, one hundred twenty-three thousand, one hundred sixty-one".