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135412738681 = 1112310248971
BaseRepresentation
bin111111000011100111…
…0100110101001111001
3110221112010221212012211
41332013032212221321
54204311130114211
6142112512535121
712532440200413
oct1760716465171
9427463855184
10135412738681
1152478a62890
12222b15514a1
13ca003b4c9c
1467a82c99b3
1537c8147e21
hex1f873a6a79

135412738681 has 4 divisors (see below), whose sum is σ = 147722987664. Its totient is φ = 123102489700.

The previous prime is 135412738661. The next prime is 135412738729. The reversal of 135412738681 is 186837214531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135412738681 - 235 = 101053000313 is a prime.

It is a super-2 number, since 2×1354127386812 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135412738631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6155124475 + ... + 6155124496.

It is an arithmetic number, because the mean of its divisors is an integer number (36930746916).

Almost surely, 2135412738681 is an apocalyptic number.

135412738681 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

135412738681 is a deficient number, since it is larger than the sum of its proper divisors (12310248983).

135412738681 is a wasteful number, since it uses less digits than its factorization.

135412738681 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12310248982.

The product of its digits is 967680, while the sum is 49.

The spelling of 135412738681 in words is "one hundred thirty-five billion, four hundred twelve million, seven hundred thirty-eight thousand, six hundred eighty-one".

Divisors: 1 11 12310248971 135412738681