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1354140433 = 23229257099
BaseRepresentation
bin101000010110110…
…1000101100010001
310111101001110110101
41100231220230101
510233124443213
6342211532401
745362001202
oct12055505421
93441043411
101354140433
11635416828
123195ba101
13187712b39
14cbbb55a9
157dd36bdd
hex50b68b11

1354140433 has 8 divisors (see below), whose sum is σ = 1419192000. Its totient is φ = 1289603568.

The previous prime is 1354140409. The next prime is 1354140443. The reversal of 1354140433 is 3340414531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1354140433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1354140443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123283 + ... + 133816.

It is an arithmetic number, because the mean of its divisors is an integer number (177399000).

Almost surely, 21354140433 is an apocalyptic number.

It is an amenable number.

1354140433 is a deficient number, since it is larger than the sum of its proper divisors (65051567).

1354140433 is a wasteful number, since it uses less digits than its factorization.

1354140433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 257351.

The product of its (nonzero) digits is 8640, while the sum is 28.

The square root of 1354140433 is about 36798.6471626336. The cubic root of 1354140433 is about 1106.3381842605.

Adding to 1354140433 its reverse (3340414531), we get a palindrome (4694554964).

The spelling of 1354140433 in words is "one billion, three hundred fifty-four million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 23 229 5267 257099 5913277 58875671 1354140433