Base | Representation |
---|---|
bin | 11001001110010110… |
… | …01000010101101001 |
3 | 1021221202220112110020 |
4 | 30213023020111221 |
5 | 210213241143144 |
6 | 10115434511053 |
7 | 656405133426 |
oct | 144713102551 |
9 | 37852815406 |
10 | 13542131049 |
11 | 581a1a8547 |
12 | 275b295489 |
13 | 137a7b85c5 |
14 | 92676ad4d |
15 | 543d3d419 |
hex | 3272c8569 |
13542131049 has 4 divisors (see below), whose sum is σ = 18056174736. Its totient is φ = 9028087364.
The previous prime is 13542131021. The next prime is 13542131063. The reversal of 13542131049 is 94013124531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13542131049 - 213 = 13542122857 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13542131149) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2257021839 + ... + 2257021844.
It is an arithmetic number, because the mean of its divisors is an integer number (4514043684).
Almost surely, 213542131049 is an apocalyptic number.
It is an amenable number.
13542131049 is a deficient number, since it is larger than the sum of its proper divisors (4514043687).
13542131049 is an equidigital number, since it uses as much as digits as its factorization.
13542131049 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4514043686.
The product of its (nonzero) digits is 12960, while the sum is 33.
The spelling of 13542131049 in words is "thirteen billion, five hundred forty-two million, one hundred thirty-one thousand, forty-nine".
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