Base | Representation |
---|---|
bin | 11001001110010111… |
… | …00110001101100011 |
3 | 1021221210010202022011 |
4 | 30213023212031203 |
5 | 210213304102121 |
6 | 10115441253351 |
7 | 656406153241 |
oct | 144713461543 |
9 | 37853122264 |
10 | 13542253411 |
11 | 581a281475 |
12 | 275b334257 |
13 | 137a82c1cb |
14 | 92679d791 |
15 | 543d647e1 |
hex | 3272e6363 |
13542253411 has 8 divisors (see below), whose sum is σ = 13561632000. Its totient is φ = 13522891200.
The previous prime is 13542253409. The next prime is 13542253423. The reversal of 13542253411 is 11435224531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13542253411 - 21 = 13542253409 is a prime.
It is a super-2 number, since 2×135422534112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13542253441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2910615 + ... + 2915263.
It is an arithmetic number, because the mean of its divisors is an integer number (1695204000).
Almost surely, 213542253411 is an apocalyptic number.
13542253411 is a deficient number, since it is larger than the sum of its proper divisors (19378589).
13542253411 is a wasteful number, since it uses less digits than its factorization.
13542253411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8189.
The product of its digits is 14400, while the sum is 31.
Adding to 13542253411 its reverse (11435224531), we get a palindrome (24977477942).
The spelling of 13542253411 in words is "thirteen billion, five hundred forty-two million, two hundred fifty-three thousand, four hundred eleven".
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