13542401225443 has 4 divisors (see below), whose sum is σ = 13558776560280. Its totient is φ = 13526025890608.

The previous prime is 13542401225407. The next prime is 13542401225491. The reversal of 13542401225443 is 34452210424531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13542401225443 is a prime.

It is a super-2 number, since 2×13542401225443² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13542401225396 and 13542401225405.

It is not an unprimeable number, because it can be changed into a prime (13542401228443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8187666178 + ... + 8187667831.

It is an arithmetic number, because the mean of its divisors is an integer number (3389694140070).

Almost surely, 2^{13542401225443} is an apocalyptic number.

13542401225443 is a deficient number, since it is larger than the sum of its proper divisors (16375334837).

13542401225443 is an equidigital number, since it uses as much as digits as its factorization.

13542401225443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16375334836.

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 13542401225443 its reverse (34452210424531), we get a palindrome (47994611649974).

The spelling of 13542401225443 in words is "thirteen trillion, five hundred forty-two billion, four hundred one million, two hundred twenty-five thousand, four hundred forty-three".