Base | Representation |
---|---|
bin | 11110110010110001001010… |
… | …010010110001100011110011 |
3 | 122202111222220101001022211011 |
4 | 132302301022102301203303 |
5 | 120222341424213304133 |
6 | 1200011430541331351 |
7 | 40345335332354635 |
oct | 3662611222614363 |
9 | 582458811038734 |
10 | 135430155213043 |
11 | 3a174673a62a59 |
12 | 13233330b66b57 |
13 | 5a750165554c2 |
14 | 2562bd69d6a55 |
15 | 109ccb0c4b6cd |
hex | 7b2c4a4b18f3 |
135430155213043 has 4 divisors (see below), whose sum is σ = 135467974304928. Its totient is φ = 135392336121160.
The previous prime is 135430155213019. The next prime is 135430155213047. The reversal of 135430155213043 is 340312551034531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135430155213043 - 217 = 135430155081971 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135430155212987 and 135430155213005.
It is not an unprimeable number, because it can be changed into a prime (135430155213047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18909540571 + ... + 18909547732.
It is an arithmetic number, because the mean of its divisors is an integer number (33866993576232).
Almost surely, 2135430155213043 is an apocalyptic number.
135430155213043 is a deficient number, since it is larger than the sum of its proper divisors (37819091885).
135430155213043 is an equidigital number, since it uses as much as digits as its factorization.
135430155213043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37819091884.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 135430155213043 in words is "one hundred thirty-five trillion, four hundred thirty billion, one hundred fifty-five million, two hundred thirteen thousand, forty-three".
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