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135430155213043 = 358137819088303
BaseRepresentation
bin11110110010110001001010…
…010010110001100011110011
3122202111222220101001022211011
4132302301022102301203303
5120222341424213304133
61200011430541331351
740345335332354635
oct3662611222614363
9582458811038734
10135430155213043
113a174673a62a59
1213233330b66b57
135a750165554c2
142562bd69d6a55
15109ccb0c4b6cd
hex7b2c4a4b18f3

135430155213043 has 4 divisors (see below), whose sum is σ = 135467974304928. Its totient is φ = 135392336121160.

The previous prime is 135430155213019. The next prime is 135430155213047. The reversal of 135430155213043 is 340312551034531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135430155213043 - 217 = 135430155081971 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135430155212987 and 135430155213005.

It is not an unprimeable number, because it can be changed into a prime (135430155213047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18909540571 + ... + 18909547732.

It is an arithmetic number, because the mean of its divisors is an integer number (33866993576232).

Almost surely, 2135430155213043 is an apocalyptic number.

135430155213043 is a deficient number, since it is larger than the sum of its proper divisors (37819091885).

135430155213043 is an equidigital number, since it uses as much as digits as its factorization.

135430155213043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37819091884.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 135430155213043 in words is "one hundred thirty-five trillion, four hundred thirty billion, one hundred fifty-five million, two hundred thirteen thousand, forty-three".

Divisors: 1 3581 37819088303 135430155213043