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1354312555201 = 9803138152867
BaseRepresentation
bin10011101101010011010…
…100011001101011000001
311210110201101000010102201
4103231103110121223001
5134142113003231301
62514055042113201
7166563061531354
oct23552324315301
94713641003381
101354312555201
114823a7148851
1219a58464b801
139a932461278
144979895029b
15253671ce201
hex13b53519ac1

1354312555201 has 4 divisors (see below), whose sum is σ = 1354450717872. Its totient is φ = 1354174392532.

The previous prime is 1354312555199. The next prime is 1354312555213. The reversal of 1354312555201 is 1025552134531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1354312555201 - 21 = 1354312555199 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1354712555201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69066631 + ... + 69086236.

It is an arithmetic number, because the mean of its divisors is an integer number (338612679468).

Almost surely, 21354312555201 is an apocalyptic number.

It is an amenable number.

1354312555201 is a deficient number, since it is larger than the sum of its proper divisors (138162671).

1354312555201 is an equidigital number, since it uses as much as digits as its factorization.

1354312555201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138162670.

The product of its (nonzero) digits is 90000, while the sum is 37.

Adding to 1354312555201 its reverse (1025552134531), we get a palindrome (2379864689732).

The spelling of 1354312555201 in words is "one trillion, three hundred fifty-four billion, three hundred twelve million, five hundred fifty-five thousand, two hundred one".

Divisors: 1 9803 138152867 1354312555201