Base | Representation |
---|---|
bin | 11001001110011110… |
… | …10111000101110011 |
3 | 1021221211222212201101 |
4 | 30213033113011303 |
5 | 210214032140201 |
6 | 10115514345231 |
7 | 656420432605 |
oct | 144717270563 |
9 | 37854885641 |
10 | 13543240051 |
11 | 581a895780 |
12 | 275b72b217 |
13 | 137aab6313 |
14 | 926979175 |
15 | 543eabd01 |
hex | 3273d7173 |
13543240051 has 8 divisors (see below), whose sum is σ = 14781164544. Its totient is φ = 12306435720.
The previous prime is 13543240027. The next prime is 13543240057. The reversal of 13543240051 is 15004234531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13543240051 - 27 = 13543239923 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13543240057) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 254655 + ... + 303208.
It is an arithmetic number, because the mean of its divisors is an integer number (1847645568).
Almost surely, 213543240051 is an apocalyptic number.
13543240051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13543240051 is a deficient number, since it is larger than the sum of its proper divisors (1237924493).
13543240051 is a wasteful number, since it uses less digits than its factorization.
13543240051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 560081.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 13543240051 its reverse (15004234531), we get a palindrome (28547474582).
The spelling of 13543240051 in words is "thirteen billion, five hundred forty-three million, two hundred forty thousand, fifty-one".
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