Base | Representation |
---|---|
bin | 10011101101010100111… |
… | …110110000001001100011 |
3 | 11210110210022110112200111 |
4 | 103231110332300021203 |
5 | 134142142122401111 |
6 | 2514101515432151 |
7 | 166563550515250 |
oct | 23552476601143 |
9 | 4713708415614 |
10 | 1354340434531 |
11 | 48241095aa17 |
12 | 19a591a55657 |
13 | 9a938172c06 |
14 | 4979c52a427 |
15 | 25369889a21 |
hex | 13b54fb0263 |
1354340434531 has 8 divisors (see below), whose sum is σ = 1547848362240. Its totient is φ = 1160840187528.
The previous prime is 1354340434529. The next prime is 1354340434549.
1354340434531 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1354340434531 - 21 = 1354340434529 is a prime.
It is a super-2 number, since 2×13543404345312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1354340434571) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1537231 + ... + 2252056.
It is an arithmetic number, because the mean of its divisors is an integer number (193481045280).
Almost surely, 21354340434531 is an apocalyptic number.
1354340434531 is a deficient number, since it is larger than the sum of its proper divisors (193507927709).
1354340434531 is an equidigital number, since it uses as much as digits as its factorization.
1354340434531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3840353.
The product of its (nonzero) digits is 518400, while the sum is 40.
It can be divided in two parts, 1354340 and 434531, that added together give a palindrome (1788871).
The spelling of 1354340434531 in words is "one trillion, three hundred fifty-four billion, three hundred forty million, four hundred thirty-four thousand, five hundred thirty-one".
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