Base | Representation |
---|---|
bin | 111111000100111000… |
… | …1000111011100101011 |
3 | 110221122010010020200201 |
4 | 1332021301013130223 |
5 | 4204403031342311 |
6 | 142121034013031 |
7 | 12533465252443 |
oct | 1761161073453 |
9 | 427563106621 |
10 | 135455340331 |
11 | 524a0010063 |
12 | 22303877177 |
13 | ca0917ca6c |
14 | 67adc19123 |
15 | 37cbc609c1 |
hex | 1f89c4772b |
135455340331 has 4 divisors (see below), whose sum is σ = 135478426000. Its totient is φ = 135432254664.
The previous prime is 135455340323. The next prime is 135455340353. The reversal of 135455340331 is 133043554531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135455340331 - 23 = 135455340323 is a prime.
It is a super-2 number, since 2×1354553403312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135455349331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11534031 + ... + 11545768.
It is an arithmetic number, because the mean of its divisors is an integer number (33869606500).
Almost surely, 2135455340331 is an apocalyptic number.
135455340331 is a deficient number, since it is larger than the sum of its proper divisors (23085669).
135455340331 is an equidigital number, since it uses as much as digits as its factorization.
135455340331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23085668.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 135455340331 its reverse (133043554531), we get a palindrome (268498894862).
The spelling of 135455340331 in words is "one hundred thirty-five billion, four hundred fifty-five million, three hundred forty thousand, three hundred thirty-one".
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