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13550131 = 731411523
BaseRepresentation
bin110011101100…
…001000110011
3221111102021201
4303230020303
511432101011
61202232031
7223113520
oct63541063
927442251
1013550131
117715461
124655617
132a6573a
141b2a147
1512c9cc1
hexcec233

13550131 has 16 divisors (see below), whose sum is σ = 16386048. Its totient is φ = 10958400.

The previous prime is 13550129. The next prime is 13550143. The reversal of 13550131 is 13105531.

13550131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13550131 - 21 = 13550129 is a prime.

It is a super-2 number, since 2×135501312 = 367212100234322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13550099 and 13550108.

It is not an unprimeable number, because it can be changed into a prime (13550111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8136 + ... + 9658.

It is an arithmetic number, because the mean of its divisors is an integer number (1024128).

Almost surely, 213550131 is an apocalyptic number.

13550131 is a deficient number, since it is larger than the sum of its proper divisors (2835917).

13550131 is a wasteful number, since it uses less digits than its factorization.

13550131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1602.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 13550131 is about 3681.0502577390. The cubic root of 13550131 is about 238.4045270656.

Adding to 13550131 its reverse (13105531), we get a palindrome (26655662).

The spelling of 13550131 in words is "thirteen million, five hundred fifty thousand, one hundred thirty-one".

Divisors: 1 7 31 41 217 287 1271 1523 8897 10661 47213 62443 330491 437101 1935733 13550131