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135511502245331 = 1021132724292111
BaseRepresentation
bin11110110011111100111010…
…111101000100110111010011
3122202210202212120211201201212
4132303330322331010313103
5120230210024033322311
61200113042534450335
740354245231624242
oct3663747275046723
9582722776751655
10135511502245331
113a1a6118270363
1213247053b039ab
135a7c8ab781934
142566b12616959
15109ee725eac8b
hex7b3f3af44dd3

135511502245331 has 4 divisors (see below), whose sum is σ = 135644226538464. Its totient is φ = 135378777952200.

The previous prime is 135511502245183. The next prime is 135511502245381. The reversal of 135511502245331 is 133542205115531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135511502245331 is a prime.

It is a super-2 number, since 2×1355115022453312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (135511502245381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 66362145035 + ... + 66362147076.

It is an arithmetic number, because the mean of its divisors is an integer number (33911056634616).

Almost surely, 2135511502245331 is an apocalyptic number.

135511502245331 is a deficient number, since it is larger than the sum of its proper divisors (132724293133).

135511502245331 is a wasteful number, since it uses less digits than its factorization.

135511502245331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 132724293132.

The product of its (nonzero) digits is 270000, while the sum is 41.

The spelling of 135511502245331 in words is "one hundred thirty-five trillion, five hundred eleven billion, five hundred two million, two hundred forty-five thousand, three hundred thirty-one".

Divisors: 1 1021 132724292111 135511502245331