Base | Representation |
---|---|
bin | 111111000110101011… |
… | …1101001010101111011 |
3 | 110221210022211111202011 |
4 | 1332031113221111323 |
5 | 4210014014203113 |
6 | 142131033150351 |
7 | 12535131026053 |
oct | 1761527512573 |
9 | 427708744664 |
10 | 135515772283 |
11 | 52521136521 |
12 | 2231bb5b3b7 |
13 | ca1884b508 |
14 | 67b7c6a563 |
15 | 37d21eb63d |
hex | 1f8d5e957b |
135515772283 has 4 divisors (see below), whose sum is σ = 135828742168. Its totient is φ = 135202802400.
The previous prime is 135515772281. The next prime is 135515772313. The reversal of 135515772283 is 382277515531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135515772283 - 21 = 135515772281 is a prime.
It is a super-2 number, since 2×1355157722832 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135515772281) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156484293 + ... + 156485158.
It is an arithmetic number, because the mean of its divisors is an integer number (33957185542).
Almost surely, 2135515772283 is an apocalyptic number.
135515772283 is a deficient number, since it is larger than the sum of its proper divisors (312969885).
135515772283 is an equidigital number, since it uses as much as digits as its factorization.
135515772283 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 312969884.
The product of its digits is 1764000, while the sum is 49.
The spelling of 135515772283 in words is "one hundred thirty-five billion, five hundred fifteen million, seven hundred seventy-two thousand, two hundred eighty-three".
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