Base | Representation |
---|---|
bin | 11001001111100010… |
… | …10111110111100011 |
3 | 1021222110202212021120 |
4 | 30213301113313203 |
5 | 210223322444011 |
6 | 10120433423323 |
7 | 656556266163 |
oct | 144761276743 |
9 | 37873685246 |
10 | 13552156131 |
11 | 5824925538 |
12 | 276270ab43 |
13 | 137c8b86c7 |
14 | 927c1a5a3 |
15 | 544b6da06 |
hex | 327c57de3 |
13552156131 has 4 divisors (see below), whose sum is σ = 18069541512. Its totient is φ = 9034770752.
The previous prime is 13552156091. The next prime is 13552156147. The reversal of 13552156131 is 13165125531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13552156131 - 27 = 13552156003 is a prime.
It is a super-2 number, since 2×135521561312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13552156092 and 13552156101.
It is not an unprimeable number, because it can be changed into a prime (13552156151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2258692686 + ... + 2258692691.
It is an arithmetic number, because the mean of its divisors is an integer number (4517385378).
Almost surely, 213552156131 is an apocalyptic number.
13552156131 is a deficient number, since it is larger than the sum of its proper divisors (4517385381).
13552156131 is an equidigital number, since it uses as much as digits as its factorization.
13552156131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4517385380.
The product of its digits is 13500, while the sum is 33.
The spelling of 13552156131 in words is "thirteen billion, five hundred fifty-two million, one hundred fifty-six thousand, one hundred thirty-one".
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