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1355230234131 = 32987559177907
BaseRepresentation
bin10011101110001010000…
…001000100011000010011
311210120002022210001021020
4103232022001010120103
5134201002414443011
62514330103130523
7166624603631214
oct23561201043023
94716068701236
101355230234131
11482828155594
1219a79ba43a43
139aa4a607757
144984478d40b
15253bca4e006
hex13b8a044613

1355230234131 has 16 divisors (see below), whose sum is σ = 1869314937600. Its totient is φ = 872317238688.

The previous prime is 1355230234103. The next prime is 1355230234139. The reversal of 1355230234131 is 1314320325531.

It is not a de Polignac number, because 1355230234131 - 213 = 1355230225939 is a prime.

It is a super-2 number, since 2×13552302341312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1355230234092 and 1355230234101.

It is not an unprimeable number, because it can be changed into a prime (1355230234139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7528680 + ... + 7706586.

It is an arithmetic number, because the mean of its divisors is an integer number (116832183600).

Almost surely, 21355230234131 is an apocalyptic number.

1355230234131 is a deficient number, since it is larger than the sum of its proper divisors (514084703469).

1355230234131 is a wasteful number, since it uses less digits than its factorization.

1355230234131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 265498.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 1355230234131 its reverse (1314320325531), we get a palindrome (2669550559662).

The spelling of 1355230234131 in words is "one trillion, three hundred fifty-five billion, two hundred thirty million, two hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 3 29 87 87559 177907 262677 533721 2539211 5159303 7617633 15477909 15577359013 46732077039 451743411377 1355230234131