Base | Representation |
---|---|
bin | 10011101110001010000… |
… | …001000100011000010011 |
3 | 11210120002022210001021020 |
4 | 103232022001010120103 |
5 | 134201002414443011 |
6 | 2514330103130523 |
7 | 166624603631214 |
oct | 23561201043023 |
9 | 4716068701236 |
10 | 1355230234131 |
11 | 482828155594 |
12 | 19a79ba43a43 |
13 | 9aa4a607757 |
14 | 4984478d40b |
15 | 253bca4e006 |
hex | 13b8a044613 |
1355230234131 has 16 divisors (see below), whose sum is σ = 1869314937600. Its totient is φ = 872317238688.
The previous prime is 1355230234103. The next prime is 1355230234139. The reversal of 1355230234131 is 1314320325531.
It is not a de Polignac number, because 1355230234131 - 213 = 1355230225939 is a prime.
It is a super-2 number, since 2×13552302341312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1355230234092 and 1355230234101.
It is not an unprimeable number, because it can be changed into a prime (1355230234139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7528680 + ... + 7706586.
It is an arithmetic number, because the mean of its divisors is an integer number (116832183600).
Almost surely, 21355230234131 is an apocalyptic number.
1355230234131 is a deficient number, since it is larger than the sum of its proper divisors (514084703469).
1355230234131 is a wasteful number, since it uses less digits than its factorization.
1355230234131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 265498.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 1355230234131 its reverse (1314320325531), we get a palindrome (2669550559662).
The spelling of 1355230234131 in words is "one trillion, three hundred fifty-five billion, two hundred thirty million, two hundred thirty-four thousand, one hundred thirty-one".
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