Search a number
-
+
135541202035 = 573371345759
BaseRepresentation
bin111111000111011100…
…0101001110001110011
3110221212002200110210211
41332032320221301303
54210042021431120
6142133342204551
712535560131221
oct1761670516163
9427762613724
10135541202035
1152534525248
1222328583757
13ca20bb31c5
1467bb3a9b11
1537d457125a
hex1f8ee29c73

135541202035 has 8 divisors (see below), whose sum is σ = 164877517440. Its totient is φ = 106947578304.

The previous prime is 135541202033. The next prime is 135541202051. The reversal of 135541202035 is 530202145531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135541202035 - 21 = 135541202033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135541201988 and 135541202006.

It is not an unprimeable number, because it can be changed into a prime (135541202033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185672515 + ... + 185673244.

It is an arithmetic number, because the mean of its divisors is an integer number (20609689680).

Almost surely, 2135541202035 is an apocalyptic number.

135541202035 is a deficient number, since it is larger than the sum of its proper divisors (29336315405).

135541202035 is an equidigital number, since it uses as much as digits as its factorization.

135541202035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 371345837.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 135541202035 its reverse (530202145531), we get a palindrome (665743347566).

The spelling of 135541202035 in words is "one hundred thirty-five billion, five hundred forty-one million, two hundred two thousand, thirty-five".

Divisors: 1 5 73 365 371345759 1856728795 27108240407 135541202035