Base | Representation |
---|---|
bin | 10011101110010111011… |
… | …010111101000101101001 |
3 | 11210120122222221121220212 |
4 | 103232113122331011221 |
5 | 134201433002430232 |
6 | 2514404255230505 |
7 | 166633304311244 |
oct | 23562732750551 |
9 | 4716588847825 |
10 | 1355455123817 |
11 | 482933098533 |
12 | 19a843218435 |
13 | 9aa85097982 |
14 | 498665b025b |
15 | 253d2672eb2 |
hex | 13b976bd169 |
1355455123817 has 4 divisors (see below), whose sum is σ = 1355467827540. Its totient is φ = 1355442420096.
The previous prime is 1355455123807. The next prime is 1355455123819. The reversal of 1355455123817 is 7183215545531.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1348069612096 + 7385511721 = 1161064^2 + 85939^2 .
It is a cyclic number.
It is not a de Polignac number, because 1355455123817 - 210 = 1355455122793 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1355455123819) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6190448 + ... + 6405665.
It is an arithmetic number, because the mean of its divisors is an integer number (338866956885).
Almost surely, 21355455123817 is an apocalyptic number.
It is an amenable number.
1355455123817 is a deficient number, since it is larger than the sum of its proper divisors (12703723).
1355455123817 is a wasteful number, since it uses less digits than its factorization.
1355455123817 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12703722.
The product of its digits is 2520000, while the sum is 50.
The spelling of 1355455123817 in words is "one trillion, three hundred fifty-five billion, four hundred fifty-five million, one hundred twenty-three thousand, eight hundred seventeen".
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