13555200313003 has 4 divisors (see below), whose sum is σ = 13556871533088. Its totient is φ = 13553529092920.

The previous prime is 13555200312911. The next prime is 13555200313051. The reversal of 13555200313003 is 30031300255531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13555200313003 - 2⁹ = 13555200312491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13555200313093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 835597876 + ... + 835614097.

It is an arithmetic number, because the mean of its divisors is an integer number (3389217883272).

Almost surely, 2^{13555200313003} is an apocalyptic number.

13555200313003 is a deficient number, since it is larger than the sum of its proper divisors (1671220085).

13555200313003 is an equidigital number, since it uses as much as digits as its factorization.

13555200313003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1671220084.

The product of its (nonzero) digits is 20250, while the sum is 31.

Adding to 13555200313003 its reverse (30031300255531), we get a palindrome (43586500568534).

The spelling of 13555200313003 in words is "thirteen trillion, five hundred fifty-five billion, two hundred million, three hundred thirteen thousand, three".