Base | Representation |
---|---|
bin | 11110110100100010111101… |
… | …010001001010100111101011 |
3 | 122202221200021212102000100021 |
4 | 132310202331101022213223 |
5 | 120231342144333134111 |
6 | 1200143515315221311 |
7 | 40360222300524646 |
oct | 3664427521124753 |
9 | 582850255360307 |
10 | 135552343255531 |
11 | 3a211475a1a854 |
12 | 13252b515a7837 |
13 | 5a836b9b45667 |
14 | 2568aa8786a5d |
15 | 10a1062d5ad71 |
hex | 7b48bd44a9eb |
135552343255531 has 4 divisors (see below), whose sum is σ = 137075403292200. Its totient is φ = 134029283218864.
The previous prime is 135552343255529. The next prime is 135552343255603.
135552343255531 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135552343255531 - 21 = 135552343255529 is a prime.
It is a super-2 number, since 2×1355523432555312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135552343255501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 761530018201 + ... + 761530018378.
It is an arithmetic number, because the mean of its divisors is an integer number (34268850823050).
Almost surely, 2135552343255531 is an apocalyptic number.
135552343255531 is a deficient number, since it is larger than the sum of its proper divisors (1523060036669).
135552343255531 is an equidigital number, since it uses as much as digits as its factorization.
135552343255531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1523060036668.
The product of its digits is 20250000, while the sum is 52.
The spelling of 135552343255531 in words is "one hundred thirty-five trillion, five hundred fifty-two billion, three hundred forty-three million, two hundred fifty-five thousand, five hundred thirty-one".
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