Base | Representation |
---|---|
bin | 10011101110011100001… |
… | …101011000001000011011 |
3 | 11210120212121002122121210 |
4 | 103232130031120020123 |
5 | 134202114033410101 |
6 | 2514420245034203 |
7 | 166635301135254 |
oct | 23563415301033 |
9 | 4716777078553 |
10 | 1355535450651 |
11 | 482974472248 |
12 | 19a8660b5963 |
13 | 9aa98910a45 |
14 | 4987311db2b |
15 | 253d973d7d6 |
hex | 13b9c35821b |
1355535450651 has 16 divisors (see below), whose sum is σ = 1865724162048. Its totient is φ = 874519800000.
The previous prime is 1355535450649. The next prime is 1355535450673. The reversal of 1355535450651 is 1560545355531.
It is not a de Polignac number, because 1355535450651 - 21 = 1355535450649 is a prime.
It is a super-3 number, since 3×13555354506513 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1355535450651.
It is not an unprimeable number, because it can be changed into a prime (1355535450151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4982590 + ... + 5247596.
It is an arithmetic number, because the mean of its divisors is an integer number (116607760128).
Almost surely, 21355535450651 is an apocalyptic number.
1355535450651 is a deficient number, since it is larger than the sum of its proper divisors (510188711397).
1355535450651 is a wasteful number, since it uses less digits than its factorization.
1355535450651 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 320042.
The product of its (nonzero) digits is 3375000, while the sum is 48.
The spelling of 1355535450651 in words is "one trillion, three hundred fifty-five billion, five hundred thirty-five million, four hundred fifty thousand, six hundred fifty-one".
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