Base | Representation |
---|---|
bin | 11001001111111100… |
… | …00011110111100001 |
3 | 1021222201000211121220 |
4 | 30213332003313201 |
5 | 210230200411311 |
6 | 10121033005253 |
7 | 656626460631 |
oct | 144776036741 |
9 | 37881024556 |
10 | 13555482081 |
11 | 5826797359 |
12 | 2763853829 |
13 | 13804b151b |
14 | 9284446c1 |
15 | 5450c9206 |
hex | 327f83de1 |
13555482081 has 4 divisors (see below), whose sum is σ = 18073976112. Its totient is φ = 9036988052.
The previous prime is 13555482079. The next prime is 13555482119. The reversal of 13555482081 is 18028455531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 18028455531 = 3 ⋅6009485177.
It is a cyclic number.
It is not a de Polignac number, because 13555482081 - 21 = 13555482079 is a prime.
It is a super-2 number, since 2×135554820812 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13555482011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2259247011 + ... + 2259247016.
It is an arithmetic number, because the mean of its divisors is an integer number (4518494028).
Almost surely, 213555482081 is an apocalyptic number.
It is an amenable number.
13555482081 is a deficient number, since it is larger than the sum of its proper divisors (4518494031).
13555482081 is an equidigital number, since it uses as much as digits as its factorization.
13555482081 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4518494030.
The product of its (nonzero) digits is 192000, while the sum is 42.
The spelling of 13555482081 in words is "thirteen billion, five hundred fifty-five million, four hundred eighty-two thousand, eighty-one".
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