Base | Representation |
---|---|
bin | 11001001111111101… |
… | …01011101011011011 |
3 | 1021222201100010022101 |
4 | 30213332223223123 |
5 | 210230221121042 |
6 | 10121040304231 |
7 | 656631040222 |
oct | 144776535333 |
9 | 37881303271 |
10 | 13555645147 |
11 | 5826898920 |
12 | 2763912077 |
13 | 138053a805 |
14 | 928487cb9 |
15 | 54510c6b7 |
hex | 327fabadb |
13555645147 has 16 divisors (see below), whose sum is σ = 15686600832. Its totient is φ = 11577121920.
The previous prime is 13555645141. The next prime is 13555645199. The reversal of 13555645147 is 74154655531.
It is a cyclic number.
It is not a de Polignac number, because 13555645147 - 215 = 13555612379 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13555645097 and 13555645106.
It is not an unprimeable number, because it can be changed into a prime (13555645141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36028 + ... + 168550.
It is an arithmetic number, because the mean of its divisors is an integer number (980412552).
Almost surely, 213555645147 is an apocalyptic number.
13555645147 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
13555645147 is a deficient number, since it is larger than the sum of its proper divisors (2130955685).
13555645147 is a wasteful number, since it uses less digits than its factorization.
13555645147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 133098.
The product of its digits is 1260000, while the sum is 46.
The spelling of 13555645147 in words is "thirteen billion, five hundred fifty-five million, six hundred forty-five thousand, one hundred forty-seven".
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