Base | Representation |
---|---|
bin | 10011101110101010001… |
… | …100101010011111111001 |
3 | 11210121110221201100102020 |
4 | 103232222030222133321 |
5 | 134203104124113021 |
6 | 2514455431225053 |
7 | 166644151041534 |
oct | 23565214523771 |
9 | 4717427640366 |
10 | 1355770144761 |
11 | 482a849a141a |
12 | 19a910818189 |
13 | 9ab054247b6 |
14 | 49896373a1b |
15 | 2540014c7c6 |
hex | 13baa32a7f9 |
1355770144761 has 4 divisors (see below), whose sum is σ = 1807693526352. Its totient is φ = 903846763172.
The previous prime is 1355770144727. The next prime is 1355770144777. The reversal of 1355770144761 is 1674410775531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1355770144761 - 29 = 1355770144249 is a prime.
It is a super-2 number, since 2×13557701447612 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1355770144061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225961690791 + ... + 225961690796.
It is an arithmetic number, because the mean of its divisors is an integer number (451923381588).
Almost surely, 21355770144761 is an apocalyptic number.
It is an amenable number.
1355770144761 is a deficient number, since it is larger than the sum of its proper divisors (451923381591).
1355770144761 is an equidigital number, since it uses as much as digits as its factorization.
1355770144761 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 451923381590.
The product of its (nonzero) digits is 2469600, while the sum is 51.
The spelling of 1355770144761 in words is "one trillion, three hundred fifty-five billion, seven hundred seventy million, one hundred forty-four thousand, seven hundred sixty-one".
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