Base | Representation |
---|---|
bin | 111111001001101001… |
… | …1001101010010110001 |
3 | 110222001021001121212001 |
4 | 1332103103031102301 |
5 | 4210220002201423 |
6 | 142144545534001 |
7 | 12540446536036 |
oct | 1762323152261 |
9 | 428037047761 |
10 | 135615272113 |
11 | 52572316192 |
12 | 22349344301 |
13 | ca33348459 |
14 | 67c716b38d |
15 | 37dad02cad |
hex | 1f934cd4b1 |
135615272113 has 4 divisors (see below), whose sum is σ = 137639380720. Its totient is φ = 133591163508.
The previous prime is 135615272059. The next prime is 135615272129. The reversal of 135615272113 is 311272516531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 135615272113 - 217 = 135615141041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (135615272183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1012054203 + ... + 1012054336.
It is an arithmetic number, because the mean of its divisors is an integer number (34409845180).
Almost surely, 2135615272113 is an apocalyptic number.
It is an amenable number.
135615272113 is a deficient number, since it is larger than the sum of its proper divisors (2024108607).
135615272113 is an equidigital number, since it uses as much as digits as its factorization.
135615272113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2024108606.
The product of its digits is 37800, while the sum is 37.
Adding to 135615272113 its reverse (311272516531), we get a palindrome (446887788644).
The spelling of 135615272113 in words is "one hundred thirty-five billion, six hundred fifteen million, two hundred seventy-two thousand, one hundred thirteen".
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