Search a number
-
+
135615341443 = 609122264873
BaseRepresentation
bin111111001001101001…
…1011110001110000011
3110222001021012010221211
41332103103132032003
54210220011411233
6142144551230551
712540450245131
oct1762323361603
9428037163854
10135615341443
115257236328a
1222349378457
13ca33370b8a
1467c7188751
1537dad185cd
hex1f934de383

135615341443 has 4 divisors (see below), whose sum is σ = 135637612408. Its totient is φ = 135593070480.

The previous prime is 135615341441. The next prime is 135615341461. The reversal of 135615341443 is 344143516531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135615341443 - 21 = 135615341441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135615341396 and 135615341405.

It is not an unprimeable number, because it can be changed into a prime (135615341441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11126346 + ... + 11138527.

It is an arithmetic number, because the mean of its divisors is an integer number (33909403102).

Almost surely, 2135615341443 is an apocalyptic number.

135615341443 is a deficient number, since it is larger than the sum of its proper divisors (22270965).

135615341443 is an equidigital number, since it uses as much as digits as its factorization.

135615341443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22270964.

The product of its digits is 259200, while the sum is 40.

Adding to 135615341443 its reverse (344143516531), we get a palindrome (479758857974).

The spelling of 135615341443 in words is "one hundred thirty-five billion, six hundred fifteen million, three hundred forty-one thousand, four hundred forty-three".

Divisors: 1 6091 22264873 135615341443